- the range of interest or activity that can be anticipated; "It is beyond the horizon of present knowledge" (同)view, purview
- the line at which the sky and Earth appear to meet (同)apparent horizon, visible horizon, sensible horizon, skyline
- the great circle on the celestial sphere whose plane passes through the sensible horizon and the center of the Earth (同)celestial horizon
- a specific layer or stratum of soil or subsoil in a vertical cross section of land
- parallel to or in the plane of the horizon or a base line; "a horizontal surface"
- something that is oriented horizontally
- in a horizontal direction; "a gallery quite often is added to make use of space vertically as well as horizontally"
- absorption into a single firm of several firms involved in the same level of production and sharing resources at that level (同)horizontal combination

- 『地平線』,水平線 / (知識・関心・経験などの)限界,範囲,視野《+『of』+『名』》
- 『水平線の』,地平線の;水平の,水平面の / 水平の位置;水平線(面)
- 水平に,横に

出典(authority):フリー百科事典『ウィキペディア（Wikipedia）』「2017/12/31 05:13:47」(JST)

**ホライズン**、または**ホライゾン**（英語：horizon）

- 地平線・水平線の総称
- 地平面
- 水平
- 乗り物などの名
- ホンダ・ホライゾン - 本田技研工業が販売していたいすゞ・ビッグホーンのOEM車種。
- ホンダ・CBX750ホライゾン - 本田技研工業が製造・販売していたオートバイの車種。
- ホライズン (列車) - アムトラックの客車のシリーズ名。「ホライゾン客車」。w:en:Horizon (railcar)参照。
- ホライゾン航空 - アラスカ航空系列のリージョナルエアライン。
- ホライズン計画 - フランス・イギリス・イタリアのフリゲート共同開発計画。またそれによって建造されたフォルバン級、アンドレア・ドリア級駆逐艦。
- ホライゾン (客船) - セレプリティクルーズ社のクルーズ客船。

- 音楽作品名
- HORIZON (UAの曲) - 1995年に発売されたUAのデビュー・シングル。
- HORIZON (HYDEの曲) - HYDEのシングル曲。
- HORIZON (レミオロメンのアルバム) - レミオロメンのアルバム。
- HORIZON (諫山実生の曲) - 諫山実生のシングル曲。
- HORIZON (清春の曲) - 清春のシングル曲。
- HORIZON - 嵐の曲。シングル「SUNRISE日本/HORIZON」に収録。
- HORIZON (cuneのアルバム) - cuneのライブアルバム。
- Horizon (今井麻美の曲) - 今井麻美のシングル曲。
- Horizon - TUBEの曲。アルバム『終わらない夏に』に収録。
- Horizon (浅岡雄也のアルバム) - 浅岡雄也のアルバム。
- Horizon - 04 Limited Sazabysの曲。アルバム『eureka』に収録。
- Horizon - Alfred Beach Sandal + STUTSの曲。アルバム『ABS+STUTS』に収録。
- Horizon (THE YELLOW MONKEYの曲) - THE YELLOW MONKEYのシングル曲。
- ホライズン - SKE48（愛知トヨタ選抜）の曲。アルバム『革命の丘』に収録。
- Over the horizon - Samsung製スマートフォンに収録されており初期設定されている着信音。

- その他
- 内藤ホライゾン - 2ちゃんねるのAAキャラクター。
- HORIZON (漫画) - 菊田洋之のラグビー漫画。
- ホライゾン (お笑い) - 双子のお笑いコンビ。
- 境界線上のホライゾン - 川上稔のライトノベル、TVアニメ。
- エースコンバット アサルト・ホライゾン - バンダイナムコゲームスのゲームソフト。
- ホライゾン - プロレスラー洞口義浩のかつてのリングネーム。
- ホライゾン ゼロ・ドーン - ソニー・インタラクティブエンタテインメントのゲームソフト。

- ニューホライズン

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For other uses, see Horizon (disambiguation).

The **horizon** or **skyline** is the apparent line that separates earth from sky, the line that divides all visible directions into two categories: those that intersect the Earth's surface, and those that do not. At many locations, the true horizon is obscured by trees, buildings, mountains, etc., and the resulting intersection of earth and sky is called the *visible horizon*. When looking at a sea from a shore, the part of the sea closest to the horizon is called the *offing*.^{[1]} The word *horizon* derives from the Greek "ὁρίζων κύκλος" *horizōn kyklos*, "separating circle",^{[2]} from the verb ὁρίζω *horizō*, "to divide", "to separate",^{[3]} and that from "ὅρος" (*oros*), "boundary, landmark".^{[4]}

- 1 Appearance and usage
- 2 Distance to the horizon
- 2.1 Other planets
- 2.2 Geometrical model
- 2.3 Approximate geometrical formulas
- 2.4 Exact formula for a spherical Earth
- 2.5 Objects above the horizon
- 2.6 Effect of atmospheric refraction

- 3 Curvature of the horizon
- 4 Vanishing points
- 5 See also
- 6 References
- 7 Further reading
- 8 External links

Historically, the distance to the visible horizon has long been vital to survival and successful navigation, especially at sea, because it determined an observer's maximum range of vision and thus of communication, with all the obvious consequences for safety and the transmission of information that this range implied. This importance lessened with the development of the radio and the telegraph, but even today, when flying an aircraft under visual flight rules, a technique called attitude flying is used to control the aircraft, where the pilot uses the visual relationship between the aircraft's nose and the horizon to control the aircraft. A pilot can also retain his or her spatial orientation by referring to the horizon.

In many contexts, especially perspective drawing, the curvature of the Earth is disregarded and the horizon is considered the theoretical line to which points on any horizontal plane converge (when projected onto the picture plane) as their distance from the observer increases. For observers near sea level the difference between this *geometrical horizon* (which assumes a perfectly flat, infinite ground plane) and the *true horizon* (which assumes a spherical Earth surface) is imperceptible to the naked eye^{[dubious – discuss]} (but for someone on a 1000-meter hill looking out to sea the true horizon will be about a degree below a horizontal line).

In astronomy the horizon is the horizontal plane through the eyes of the observer. It is the fundamental plane of the horizontal coordinate system, the locus of points that have an altitude of zero degrees. While similar in ways to the geometrical horizon, in this context a horizon may be considered to be a plane in space, rather than a line on a picture plane.

One typically sees further along the Earth's curved surface than a simple geometric calculation allows for because of refraction error. If the ground, or water, surface is colder than the air above it, a cold, dense layer of air forms close to the surface, causing light to be refracted downward as it travels, and therefore, to some extent, to go around the curvature of the Earth. The reverse happens if the ground is hotter than the air above it, as often happens in deserts, producing mirages. As an approximate compensation for refraction, surveyors measuring distances longer than 300 feet subtract 14% from the calculated curvature error and ensure lines of sight are at least 5 feet from the ground, to reduce random errors created by refraction.

However, ignoring the effect of atmospheric refraction, distance to the horizon from an observer close to the Earth's surface is about^{[5]}

- $d\approx 3.57{\sqrt {h}}\,,$

where *d* is in kilometres and *h* is height above ground level in metres. The constant 3.57 has units of km/m^{½}.

Examples:

- For an observer standing on the ground with
*h*= 1.70 metres (5 ft 7 in), the horizon is at a distance of 4.7 kilometres (2.9 mi). - For an observer standing on the ground with
*h*= 2 metres (6 ft 7 in), the horizon is at a distance of 5 kilometres (3.1 mi). - For an observer standing on a hill or tower of 100 metres (330 ft) in height, the horizon is at a distance of 36 kilometres (22 mi).
- For an observer standing at the top of the Burj Khalifa (828 metres (2,717 ft) in height), the horizon is at a distance of 103 kilometres (64 mi).
- For an observer atop Mount Everest (8,848 metres (29,029 ft) in altitude), the horizon is at a distance of 336 kilometres (209 mi).

With *d* in miles (i.e. "land miles" of 5,280 feet (1,609.344 m)^{[5]}) and *h* in feet,

- $d\approx {\sqrt {1.5h}}\approx 1.22{\sqrt {h}}\,.$

Where the constant 1.22 has units of mi/ft^{½}. Examples, assuming no refraction:

- For an observer on the ground with eye level at
*h*= 5 ft 7 in (1.70 m), the horizon is at a distance of 2.9 miles (4.7 km). - For an observer standing on a hill or tower 100 feet (30 m) in height, the horizon is at a distance of 12.2 miles (19.6 km).
- For an observer on the summit of Aconcagua (22,841 feet (6,962 m) in height), the sea-level horizon to the west is at a distance of 184 miles (296 km).
- For a U-2 pilot, whilst flying at its service ceiling 70,000 feet (21,000 m), the horizon is at a distance of 324 miles (521 km)

On terrestrial planets and other solid celestial bodies with negligible atmospheric effects, the distance to the horizon for a "standard observer" varies as the square root of the planet's radius. Thus, the horizon on Mercury is 62% as far away from the observer as it is on Earth, on Mars the figure is 73%, on the Moon the figure is 52%, on Mimas the figure is 18%, and so on.

If the Earth is assumed to be a featureless sphere (rather than an oblate spheroid) with no atmospheric refraction, then the distance to the horizon can easily be calculated.^{[6]}

The secant-tangent theorem states that

- $\mathrm {OC} ^{2}=\mathrm {OA} \times \mathrm {OB} \,.$

Make the following substitutions:

*d*= OC = distance to the horizon*D*= AB = diameter of the Earth*h*= OB = height of the observer above sea level*D+h*= OA = diameter of the Earth plus height of the observer above sea level

The formula now becomes

- $d^{2}=h(D+h)\,\!$

or

- $d={\sqrt {h(D+h)}}={\sqrt {h(2R+h)}}\,,$

where *R* is the radius of the Earth.

The equation can also be derived using the Pythagorean theorem. Since the line of sight is a tangent to the Earth, it is perpendicular to the radius at the horizon. This sets up a right triangle, with the sum of the radius and the height as the hypotenuse. With

*d*= distance to the horizon*h*= height of the observer above sea level*R*= radius of the Earth

referring to the second figure at the right leads to the following:

- $(R+h)^{2}=R^{2}+d^{2}\,\!$
- $R^{2}+2Rh+h^{2}=R^{2}+d^{2}\,\!$
- $d={\sqrt {h(2R+h)}}\,.$

Another relationship involves the distance *s* along the curved surface of the Earth to the horizon; with *γ* in radians,

- $s=R\gamma \,;$

then

- $\cos \gamma =\cos {\frac {s}{R}}={\frac {R}{R+h}}\,.$

Solving for *s* gives

- $s=R\cos ^{-1}{\frac {R}{R+h}}\,.$

The distance *s* can also be expressed in terms of the line-of-sight distance *d*; from the second figure at the right,

- $\tan \gamma ={\frac {d}{R}}\,;$

substituting for *γ* and rearranging gives

- $s=R\tan ^{-1}{\frac {d}{R}}\,.$

The distances *d* and *s* are nearly the same when the height of the object is negligible compared to the radius (that is, *h* ≪ *R*).

If the observer is close to the surface of the earth, then it is valid to disregard *h* in the term (2*R* + *h*), and the formula becomes-

- $d={\sqrt {2Rh}}\,.$

Using kilometres for *d* and *R*, and metres for *h*, and taking the radius of the Earth as 6371 km, the distance to the horizon is

- $d\approx {\sqrt {2\cdot 6371\cdot {h/1000}}}\approx 3.570{\sqrt {h}}\,,$.

Using imperial units, with *d* and *R* in statute miles (as commonly used on land), and *h* in feet, the distance to the horizon is

- $d\approx {\sqrt {2\cdot 3963\cdot {h/5280}}}\approx {\sqrt {1.5h}}\approx 1.22{\sqrt {h}}$.

If *d* is in nautical miles, and *h* in feet, the constant factor is about 1.06, which is close enough to 1 that it is often ignored, giving:

- $d\approx {\sqrt {h}}$

These formulas may be used when *h* is much smaller than the radius of the Earth (6371 km or 3959 mi), including all views from any mountaintops, airplanes, or high-altitude balloons. With the constants as given, both the metric and imperial formulas are precise to within 1% (see the next section for how to obtain greater precision).

If *h* is significant with respect to *R*, as with most satellites, then the approximation made previously is no longer valid, and the exact formula is required:

- $d={\sqrt {2Rh+h^{2}}}\,,$

where *R* is the radius of the Earth (*R* and *h* must be in the same units). For example, if a satellite is at a height of 2000 km, the distance to the horizon is 5,430 kilometres (3,370 mi); neglecting the second term in parentheses would give a distance of 5,048 kilometres (3,137 mi), a 7% error.

To compute the greatest distance at which an observer can see the top of an object above the horizon, compute the distance to the horizon for a hypothetical observer on top of that object, and add it to the real observer's distance to the horizon. For example, for an observer with a height of 1.70 m standing on the ground, the horizon is 4.65 km away. For a tower with a height of 100 m, the horizon distance is 35.7 km. Thus an observer on a beach can see the top of the tower as long as it is not more than 40.35 km away. Conversely, if an observer on a boat (*h* = 1.7 m) can just see the tops of trees on a nearby shore (*h* = 10 m), the trees are probably about 16 km away.

Referring to the figure at the right, the top of the lighthouse will be visible to a lookout in a crow's nest at the top of a mast of the boat if

- $D_{\mathrm {BL} }<3.57\,({\sqrt {h_{\mathrm {B} }}}+{\sqrt {h_{\mathrm {L} }}})\,,$

where *D*_{BL} is in kilometres and *h*_{B} and *h*_{L} are in metres.

As another example, suppose an observer, whose eyes are two metres above the level ground, uses binoculars to look at a distant building which he knows to consist of thirty storeys, each 3.5 metres high. He counts the storeys he can see, and finds there are only ten. So twenty storeys or 70 metres of the building are hidden from him by the curvature of the Earth. From this, he can calculate his distance from the building:

- $D\approx 3.57({\sqrt {2}}+{\sqrt {70}})$

which comes to about 35 kilometres.

It is similarly possible to calculate how much of a distant object is visible above the horizon. Suppose an observer's eye is 10 metres above sea level, and he is watching a ship that is 20 km away. His horizon is:

- $3.57{\sqrt {10}}$

kilometres from him, which comes to about 11.3 kilometres away. The ship is a further 8.7 km away. The height of a point on the ship that is just visible to the observer is given by:

- $h\approx \left({\frac {8.7}{3.57}}\right)^{2}$

which comes to almost exactly six metres. The observer can therefore see that part of the ship that is more than six metres above the level of the water. The part of the ship that is below this height is hidden from him by the curvature of the Earth. In this situation, the ship is said to be hull-down.

If the Earth were an airless world like the Moon, the above calculations would be accurate. However, Earth has an atmosphere of air, whose density and refractive index vary considerably depending on the temperature and pressure. This makes the air refract light to varying extents, affecting the appearance of the horizon. Usually, the density of the air just above the surface of the Earth is greater than its density at greater altitudes. This makes its refractive index greater near the surface than at higher altitudes, which causes light that is travelling roughly horizontally to be refracted downward.^{[7]} This makes the actual distance to the horizon greater than the distance calculated with geometrical formulas. With standard atmospheric conditions, the difference is about 8%. This changes the factor of 3.57, in the metric formulas used above, to about 3.86. This correction can be, and often is, applied as a fairly good approximation when conditions are close to standard. When conditions are unusual, this approximation fails. Refraction is strongly affected by temperature gradients, which can vary considerably from day to day, especially over water. In extreme cases, usually in springtime, when warm air overlies cold water, refraction can allow light to follow the Earth's surface for hundreds of kilometres. Opposite conditions occur, for example, in deserts, where the surface is very hot, so hot, low-density air is below cooler air. This causes light to be refracted upward, causing mirage effects that make the concept of the horizon somewhat meaningless. Calculated values for the effects of refraction under unusual conditions are therefore only approximate.^{[5]} Nevertheless, attempts have been made to calculate them more accurately than the simple approximation described above.

Outside the visual wavelength range, refraction will be different. For radar (e.g. for wavelengths 300 to 3 mm i.e. frequencies between 1 and 100 GHz) the radius of the Earth may be multiplied by 4/3 to obtain an effective radius giving a factor of 4.12 in the metric formula i.e. the radar horizon will be 15% beyond the geometrical horizon or 7% beyond the visual. The 4/3 factor is not exact, as in the visual case the refraction depends on atmospheric conditions.

- Integration method—Sweer

If the density profile of the atmosphere is known, the distance *d* to the horizon is given by^{[8]}

- $d={{R}_{\text{E}}}\left(\psi +\delta \right)\,,$

where *R*_{E} is the radius of the Earth, *ψ* is the dip of the horizon and *δ* is the refraction of the horizon. The dip is determined fairly simply from

- $\cos \psi ={\frac {{R}_{\text{E}}{\mu }_{0}}{\left({{R}_{\text{E}}}+h\right)\mu }}\,,$

where *h* is the observer's height above the Earth, *μ* is the index of refraction of air at the observer's height, and *μ*_{0} is the index of refraction of air at Earth's surface.

The refraction must be found by integration of

- $\delta =-\int _{0}^{h}{\tan \phi {\frac {{\text{d}}\mu }{\mu }}}\,,$

where $\phi \,\!$ is the angle between the ray and a line through the center of the Earth. The angles *ψ* and $\phi \,\!$ are related by

- $\phi =90{}^{\circ }-\psi \,.$

- Simple method—Young

A much simpler approach, which produces essentially the same results as the first-order approximation described above, uses the geometrical model but uses a radius *R′* = 7/6 *R*_{E}. The distance to the horizon is then^{[5]}

- $d={\sqrt {2R^{\prime }h}}\,.$

Taking the radius of the Earth as 6371 km, with *d* in km and *h* in m,

- $d\approx 3.86{\sqrt {h}}\,;$

with *d* in mi and *h* in ft,

- $d\approx 1.32{\sqrt {h}}\,.$

Results from Young's method are quite close to those from Sweer's method, and are sufficiently accurate for many purposes.

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From a point above the surface the horizon appears slightly bent (it is a circle). There is a basic geometrical relationship between this visual curvature $\kappa$, the altitude $h$, and the Earth's radius $R$, . It is

- $\kappa ={\sqrt {\left(1+{\frac {h}{R}}\right)^{2}-1}}\ .$

The curvature is the reciprocal of the curvature angular radius in radians. A curvature of 1 appears as a circle of an angular radius of 57.3° corresponding to an altitude of approximately 2640 km above the Earth's surface. At an altitude of 10 km (33,000 ft, the typical cruising altitude of an airliner) the mathematical curvature of the horizon is about 0.056, the same curvature of the rim of circle with a radius of 10 m that is viewed from 56 cm directly above the center of the circle. However, the apparent curvature is less than that due to refraction of light in the atmosphere and because the horizon is often masked by high cloud layers that reduce the altitude above the visual surface.

Main article: Vanishing point

The horizon is a key feature of the picture plane in the science of graphical perspective. Assuming the picture plane stands vertical to ground, and *P* is the perpendicular projection of the eye point *O* on the picture plane, the horizon is defined as the horizontal line through *P*. The point *P* is the vanishing point of lines perpendicular to the picture. If *S* is another point on the horizon, then it is the vanishing point for all lines parallel to *OS*. But Brook Taylor (1719) indicated that the horizon plane determined by *O* and the horizon was like any other plane:

- The term of Horizontal Line, for instance, is apt to confine the Notions of a Learner to the Plane of the Horizon, and to make him imagine, that that Plane enjoys some particular Privileges, which make the Figures in it more easy and more convenient to be described, by the means of that Horizontal Line, than the Figures in any other plane;…But in this Book I make no difference between the Plane of the Horizon, and any other Plane whatsoever...
^{[9]}^{[10]}

The peculiar geometry of perspective where parallel lines converge in the distance, stimulated the development of projective geometry which posits a point at infinity where parallel lines meet. In her book *Geometry of an Art* (2007), Kirsti Andersen described the evolution of perspective drawing and science up to 1800, noting that vanishing points need not be on the horizon. In a chapter titled "Horizon", John Stillwell recounted how projective geometry has led to incidence geometry, the modern abstract study of line intersection. Stillwell also ventured into foundations of mathematics in a section titled "What are the Laws of Algebra ?" The "algebra of points", originally given by Karl von Staudt deriving the axioms of a field was deconstructed in the twentieth century, yielding a wide variety of mathematical possibilities. Stillwell states

- This discovery from 100 years ago seems capable of turning mathematics upside down, though it has not yet been fully absorbed by the mathematical community. Not only does it defy the trend of turning geometry into algebra, it suggests that both geometry and algebra have a simpler foundation than previously thought.
^{[11]}

- Aerial landscape art
- Atmospheric refraction
- Dawn
- Dusk
- Horizontal and vertical
- Landscape
- Landscape art

- Limb
^{[disambiguation needed]}- Limb darkening
- Lunar limb

- Sextant

**^**"Offing".*Webster's Third New International Dictionary*(Unabridged ed.). Pronounced, "Hor-I-zon".**^**Liddell, Henry George & Scott, Robert. "ὁρίζων".*A Greek-English Lexicon*. Perseus Digital Library. Archived from the original on June 5, 2011. Retrieved April 19, 2011. CS1 maint: Uses authors parameter (link)**^**Liddell, Henry George & Scott, Robert. "ὁρίζω".*A Greek-English Lexicon*. Perseus Digital Library. Archived from the original on June 5, 2011. Retrieved April 19, 2011. CS1 maint: Uses authors parameter (link)**^**Liddell, Henry George & Scott, Robert. "ὅρος".*A Greek-English Lexicon*. Perseus Digital Library. Archived from the original on June 5, 2011. Retrieved April 19, 2011. CS1 maint: Uses authors parameter (link)- ^
^{a}^{b}^{c}^{d}Young, Andrew T. "Distance to the Horizon".*Green Flash website*(Sections: Astronomical Refraction, Horizon Grouping). San Diego State University Department of Astronomy. Archived from the original on October 18, 2003. Retrieved April 16, 2011. **^**Plait, Phil (15 January 2009). "How far away is the horizon?".*Discover*. Bad Astronomy. Kalmbach Publishing Co. Archived from the original on 29 March 2017. Retrieved 2017-03-28.**^**Proctor, Richard Anthony; Ranyard, Arthur Cowper (1892).*Old and New Astronomy*. Longmans, Green and Company. p. 73. Archived from the original on 2017-03-29.**^**Sweer, John (1938). "The Path of a Ray of Light Tangent to the Surface of the Earth".*Journal of the Optical Society of America*.**28**: 327–329. doi:10.1364/JOSA.28.000327. (Subscription required (help)).**^**Taylor, Brook.*New Principles of Perspective*. p. 1719. CS1 maint: Uses authors parameter (link)**^**Anderson, Kirsti (1991). "Brook Taylor's Work on Linear Perspective". Springer. p. 151. ISBN 0-387-97486-5.**^**Stillwell, John (2006). "Yearning for the Impossible".*Horizon*. A K Peters, Ltd. pp. 47–76. ISBN 1-56881-254-X.

- Young, Andrew T. "Dip of the Horizon".
*Green Flash website*(Sections: Astronomical Refraction, Horizon Grouping). San Diego State University Department of Astronomy. Retrieved April 16, 2011.

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- NAID 120005620633

- 骨研究の最前線 : 骨を基軸とした多臓器連関システム (特集 ロコモティブシンドローム対応の機能性素材 : サルコペニア、フレイルを中心に)

- 中島 友紀
- Food style 21 19(6), 44-47, 2015-06
- NAID 40020489571

- 量子アニーリングが拓く新時代

- 大関 真之
- システム制御情報学会研究発表講演会講演論文集 59, 4p, 2015-05-20
- NAID 40020472724

リンク元 | 「horizontal」「水平」「horizontally」「水平線」 |

拡張検索 | 「horizontal axis」「horizontal disease transmission」 |

- adj.

- 水平な、水平方向の

- 水平方向に、水平に